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9n^2+222n+1360=0
a = 9; b = 222; c = +1360;
Δ = b2-4ac
Δ = 2222-4·9·1360
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{324}=18$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(222)-18}{2*9}=\frac{-240}{18} =-13+1/3 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(222)+18}{2*9}=\frac{-204}{18} =-11+1/3 $
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